Homework #1 : Population Genetics necessary)-credit may not be granted if no wor

Question

Homework #1 : Population Genetics necessary)-credit may not be granted if no work is shown. Do your own work: you can discuss this wn Due at the beginning of class, Mon 10 September. Show your w ork (you may attach additional pages as n a faraway planet (where evolution works in the same ways as it does on Earth), three predators present. These phenotypes are the result of a single gene with two alleles in Hardy- and of these, and there are 3872 of them lacking the star. classmates, but be sure you can work these problems on your own enotypes of sneetches (apologies to Theodor Geisel) all have equal fitness - this island has no Weinberg equilibrium. The homozygous dominant and heterozygous creatures have a star, a trait at is lacking in the homozygous recessive creatures. There are currently 5,000 of them in all,. 1. What are p and q for this population? ndin 1128 2. After one generation of random mating, the population increases to 8,064. How many creatures are there now without a star? A huge hurricane-like storm causes havoc on the planet-fortunately for the creatures, it is not enough to wipe out the planet. However, it happened to strike at a celebration of the starless sneetches, and 2,432 of these were killed. (Begin with the larger population of 8,064.) 3. What are the new values for p and q? :3872-24324 4. Is this population in Hardy-Weinberg equilibrium? 5. Briefly explain why the population is (or is noty in HWE. (Beware tautologies!)

Explanation / Answer

1.According to the equation p+q=1 hence

p=0.2256

q=0.7744

3. p= 0.620

q= 0.379

4. Yes. If p and q value is changed then it is Hardy wienberg equilibrium.

5. Only recessive individuals are killed so it is called as genetic drift. Genetic drift changes Gene frequency hence Hardy weinWein equilibrium is altered.

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