Centripetal Force A puck of mass m = 1.52 kg slides in a circle of radius r = 16

Question

Centripetal Force

A puck of mass m = 1.52 kg slides in a circle of radius r = 16.4 cm on a frictionless table while attached to a hanging cylinder of mass M = 2.83 kg by means of a cord that extends through a hole in the table (as shown in the figure). What is the required force of tension on M to keep it from falling? How do the tensions acting on M and m compare? Incorrect The tension on M is greater than the tension on m. Correct: They are equal. Incorrect The tension on M is less than the tension on m. What is speed of the puck that keeps the cylinder at rest?

Explanation / Answer

Here ,

for the required force of tension to keep M from falling

T = M * g

T = 2.83 * 9.8 N

T = 27.7 N

the tension in wire must be 27.7 N
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as the string is same

tension acting on M and m is same

they are equal
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let the speed of puck is v

Using second law of motion

T = m * v^2/r

27.7 = 1.52 * v^2/0.164

solving for v

v = 1.73 m/s

the speed of puck will be 1.73 m/s

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