1)The normal force equals the magnitude of the gravitational force as a roller c

Question

1)The normal force equals the magnitude of the gravitational force as a roller coaster car crosses the top of a 39-m-diameter loop-the-loop.

What is the car's speed at the top?

2)A new car is tested on a 280-m-diameter track.

If the car speeds up at a steady 1.2 m/s2 , how long after starting is the magnitude of its centripetal acceleration equal to the tangential acceleration?

3)A concrete highway curve of radius 70.0 m is banked at a 17.0 angle.

What is the maximum speed with which a 1100 kg rubber-tired car can take this curve without sliding? (Take the static coefficient of friction of rubber on concrete to be 1.0.)

Explanation / Answer

Multiple questions I am allowed to answer only 1 question at a time According to the chegg guidelines.

Question 1) F = 2 * m * g = mv^2 /r ( m gets eliminated and rearrange for v we get )

v =sqrt ( 2 * g * r ) = sqrt ( 2.0 * 9.8 * 19.5 m ) = 19.55 m/s =============ANSWER)

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