A charged capacitor stores energy U. Without connecting this capacitor to anythi

Question

A charged capacitor stores energy U. Without connecting this capacitor to anything, dielectric having dielectric constant K is now inserted between the plates of the capacitor, completely filling the space between them. How much energy does the capacitor now store? 2 KU KU U UK UK The graph in the figure shows the variation of the electric potential V (measured in volts) as a function of the radial direction r (measured in meters). For which range or value of r is the magnitude of the electric field the largest? from r = 0 m to r = 3 m from r = 3 m to r = 4 m from r = 4 m to r = 6m at r = 3 m at r = 4 m

Explanation / Answer

U/K

The energy stored in the capacitor is given by,U=Q2/2C

Q= charge stored in the capacitor

C=Capacitence of the capacitor

Putting a dielectric between the plates changes C to Kc and thus U to U/K

b) from r=3 m to r= 4 m

The electric field is maximum at r=3 and minimum at r=4 m

Electric field |E|=|dv/dr|

That is the greater the change in potential larger is the electric field produced. The rate of change of potential is maximum at r=3 m to r= 4m . SO the electric field is maxium at this point.

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