As shown in the figure below, a coil that is square, has 30 turns, is 0.82 ?, an

Question

As shown in the figure below, a coil that is square, has 30 turns, is 0.82 ?, and is 13.0 cm on a side is between the poles of a large electromagnet that produces a constant, uniform magnetic field of 0.5 T directed into the page. As suggested by the figure, the field drops sharply to zero at the edges of the magnet. The coil moves to the right at a constant velocity of 2.00 cm/s. What is the current through the coil wire in the following instances?

(a) before the coil reaches the edge of the field
A

(b) while the coil is leaving the field
A

(c) after the coil leaves the field
A

(d) What is the total charge that flows past a given point in the coil as it leaves the field?

Explanation / Answer

given,

no.of turns N=30

resistance of coil R=0.82 ohm

side length of coil, l=13.0 cm

area of the coil A = l^2 = 169*10^-4 m^2

magnetic field B=0.5 T

velocity of the coil v=2 cm/sec

current i = E/R

Part (a)

before the coil reaches the edge of the field

change in flux = 0
E = 0
I = 0

Part (b)

while the coil is leaving the field

change in flux = N*(B2-B1)*A
emf = E = -rate of chage in flux

E = N*(B2-B1)*l*l/t = N*(B2-B1)*l*v
i = E/R

i = (30*0.5*0.13*0.02)/0.82
i = 0.048 A <<<<<---------------answer

Part (c)

after the coil leaves the field, there won't by any change in magnetic flux.

Hence, curent through the coil leaves the field is 0A

out side B = 0
i = 0

Part (d)

What is the total charge that flows past a given point in the coil as it leaves the field?
Q = i*t = i*l/v = 0.048*0.13/(0.02)=0.312 C    

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