A 2.00 kg block is release from point A as shown in the figure below. The curved

Question

A 2.00 kg block is release from point A as shown in the figure below. The curved portion on the track is frictionless. The horizontal track, including the portion under string, has a kinetics coefficient of friction muk=0.10. a) What is the block's velocity at point B? b) What is block's velocity at point C where the spring's length is equal to its natural length? c) How much does the block compress the spring (k=30.0 N/m) before coming momentarily to rest? d) Where does the block ultimately come to rest?

Explanation / Answer

a) net Energy at A=net energy at B

(KE+PE)A=(KE+PE)B

0+1.5(mg)=0.5mv2+0

v=5.422m/s

b)retardation = µg

v2=u2+2as

v2=5.4222-2(0.1*9.8)10

v=3.13m/s

c)Energy conserve

0.5m(3.13)2=0.5*30*x2

x=0.808m

d)then spring again releases,block gains its velocity=3.13m/s then again friction surface

v2=u2+2as

v2=3.132-2(0.1*9.8)x

x=5m

i.e. 5m from right of B and also we can say 5 m from left of C

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.