The figure below is a cross-sectional view of a coaxial cable. The center conduc

Question

The figure below is a cross-sectional view of a coaxial cable. The center conductor is surrounded by a rubber layer, an outer conductor, and another rubber layer. In a particular application, the current in the inner conductor is I1 = 1.06 A out of the page and the current in the outer conductor is I2 = 3.16 A into the page. Assuming the distance d = 1.00 mm, answer the following.

(a) Determine the magnitude and direction of the magnetic field at point a.

(b) Determine the magnitude and direction of the magnetic field at point b.

magnitude _____µT direction ---Select--- to the left to the right upward downward into the page out of the page

Explanation / Answer

a) Using Ampere's Law,

magnetic flux through closed loop = B.L = u0 Iin

B ( 2 pi d ) = u0 I1

B = (4pi x 10^-7 x 1.06 ) / (2 pi 0.001 )

B = 2.12 x 10^-4 T = 212 uT

direction -> upwards

b)

B ( 2pi (d+d+d) ) = u0 (I2 - I1)

B = (4pi x 10^-7 x (3.16-1.06)) / (2 pi 0.003 )

B = 1.4 x 10^-4 T = 140 uT

direction - ? downwards

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