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A small glass bead has been charged to+ 20 nC . Part A) What is the the accelera

ID: 1425788 • Letter: A

Question

A small glass bead has been charged to+ 20 nC .

Part A)

What is the the acceleration of a proton that is 3.5 cm from the center of the bead? Input positive value if the acceleration is derected toward the bead and negative if it is directed away from the bead.

a(p+) = _______ ________(units)

Part B)

What is the the acceleration of an electron that is 3.5 cm from the center of the bead? Input positive value if the acceleration is derected toward the bead and negative if it is directed away from the bead.

a(e-)= __________ ___________ (units)

Explanation / Answer

electrostatic force between two charges is given by

F = kq1q2/r2

a) q1 = 20 nC

q2 = 1.6 x 10-19C

r = 3.5 cm = 3.5 x 10-2 m

F = 2.35 x 10-24 N

acceleration of proton

a = F/m = -1.407 x 103 m/s2

b) a = F/m = 2.58 x 106 m/s2

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