Consider an electron going around the circuit shown (the top picture is a “real-

Question

Consider an electron going around the circuit shown (the top picture is a “real-life” representation of the circuit, the bottom picture is a schematic of the same circuit). Electrons have a charge of –e, so going from the + to – terminal of the battery will result in a gain of 9 eV of energy. If the electron loses 5 eV of energy going through bulb 1, what will be the energy change of the electron when it moves through bulb 2 in the direction indicated? Assume the wires in the circuit have no resistance.

Explanation / Answer

Simply by conservation of energy principle; the electron will lose 4eV energy on second bulb where it has no energy, then agin the battery will provide it an energy of 9eV

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