You are using a pulley system to lift a hanging weight. You arrange the pulleys

Question

You are using a pulley system to lift a hanging weight. You arrange the pulleys as shown in the diagram below, and pull down on the end of the rope with a force of 20 N. As you pull, the end of the rope moves a distance of 0.1 m downward. On the diagram, drag the appropriate labels to indicate both the amount of work (in joules) that you do while pulling the rope, and the amount of work done by the pulley on the hanging weight. Assume that the pulley itself is mass less, and that friction is negligible.

Explanation / Answer

let tension in the rope is T.

balaning force on the rope:

T=20 N

consider the pulley that is being conneted to hanging mass.

force acting on the hanging weight by the pulley=2*T=40 N

work done by the 20 N force=force * distance travelled=20*0.1=2 J

when the rope goes down by 0.1 m,

the two parts of the rope conneted to the pulley will go up by 0.1 m/2=0.05 m eah

hence the hanging weight will move upward by a distance of 0.05 M

work done by pulley on hanging weight=force applied*distane travelled

=40*0.05=2 J

hene work in=2 J

work out=2 J

Related Questions

Navigate

• Browse (All)
• Browse Y
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.