Four identical metallic spheres with charges of +7.8 µC, +6.6 µC, 8.6 µC, and 3.

Question

Four identical metallic spheres with charges of +7.8 µC, +6.6 µC, 8.6 µC, and 3.2 µC are placed on a piece of paper. The paper is lifted on all corners so that the spheres come into contact with each other simultaneously. The paper is then flattened so that the metallic spheres become separated.

(a) What is the resulting charge on each sphere? _____.65_____ µC GOT PART A NEED HELP WITH WHAT THE ANSWER IS FOR PART B

(b) How many excess or absent electrons (depending on the sign of your answer to part (a)) correspond to the resulting charge on each sphere? __________ electrons are ---Select--- absent or in excess

(a) Since all the metallic sphere are identical hence final charge on them will be equal and must be average of all the charge. So

Explanation / Answer

ne = +0.65* 10^-6C .. .. n = number of absent electrons each with charge e

n = 0.65* 10^-6C / 1.6.*10^-19 C/e .. .. n =0.40625 * 10^ -13 absent electrons (giving +ve charge)

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