A. The electric field created at point P1 by charge Q1 has a magnitude of: B. Th

Question

A. The electric field created at point P1 by charge Q1 has a magnitude of:

B. The electric field created at point P1 by charge Q1 is directed:

C. The total electric field at point P1 is equal to:

D. If a third particle having charge Q3 ? ? 2.00 ? C is brought from infinity to the point P1, the change in the electric potential energy of the system would equal:

E. The electric field created at point P2 by charge Q1 is directed:

F. The electric field created at point P2 by charge Q2 has a magnitude of:

G. The electric field created at point P2 by charge Q2 is directed:

H. The scalar x component of the total electric field at point P2 equals:

I. The scalar y component of the total electric field at point P2 equals:

J. If a third charge Q3 = - 2.00 micro-coulombs were placed at point P2, Q3 would experience an electrostatic force directed:

The figure below shows two point particles having charges Q1- -2 and 02-2 where Q= 0.100 C . Suppose that the two charged particles are held fixed in position. Q = 0.100 pC "P1" and "P2" are just points in the x-y plane; they are not charged particles. 800 cm The point "P1" is located midway between the two charged particles. I P 30 cm P2

Explanation / Answer

D. If a third particle having charge Q3 2.00 C is brought from infinity to the point P1, the change in the electric potential energy of the system would equal:

Answers : -
A. The electric field created at point P1 by charge Q1 has a magnitude of:
E = k*q/r^2 = (8.9* 10^3 * 0.1 )/(4*10^-2)^2
   E = 5.56 * 10^5 N/C

B. The electric field created at point P1 by charge Q1 is directed: To the Left.

C. The total electric field at point P1 is equal to: = 2* E
   Enet = 1.112 * 10^6 N/C

D.
Potential At Point P1 is 0 Due to two Charges present, Therefore
change in the electric potential energy of the system would equal: 0

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