A person with refractice myopia can see objects as close as 25 cm clearly, and o

Question

A person with refractice myopia can see objects as close as 25 cm clearly, and objects as far away as 3 m clearly.

a) what is the max optical power of this person's eye?

b) what is the min optical power of this person's eye?

c) what is the range of accomodation of this person's eye?

The person gets a set of contact lenses for their eyes to correct their far vision. When they are wearing the contact lenses they can see objects in the distance clearly.

d) What is the optical power of the contact lenses?

e) what is the person's new near point?

f) what is the range of accomadation of this new person when wearing their contact lenses?

Explanation / Answer

I am allowed to answer only 1 question at a time
1st 3 parts constitute 1 question

Genral didtance between lens and retina is 2 cm
a)
s = 25cm = 0.25 m
s' = 2 cm = 0.02 m
1/f = 1/s' + 1/s
p = 1/0.02 + 1/0.25
    =54 D

b)
s = 3 m
s' = 2 cm = 0.02 m
1/f = 1/s' + 1/s
p = 1/0.02 + 1/3
    =50.3 D

c)
range of accomodation = 54 - 50.3 = 3.7 D
from 50.3 D to 54 D

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