A proton moves at a speed of 1,210 m/s in a direction perpendicular to a magneti

Question

A proton moves at a speed of 1,210 m/s in a direction perpendicular to a magnetic field with a magnitude of 0.76 T. If the proton is replaced with an electron, how will the magnitude of the force change? |Felectron| |Fproton| = ?

How will the direction of the force change?

a. The force on the electron will be in the same direction as the force on the proton.

b. The force on the electron will be at a 45° angle to the force on the proton.

c.The force on the electron will be in the opposite direction as the force on the proton.

d. The force on the electron will be perpendicular to the force on the proton.

Explanation / Answer

magnetic force is given as

F = q V B

since q , V and B are same for both electron and proton , hence they experience same amount of force

Felectron = Fproton

Felectron / Fproton = 1

direction of force on electron will be opposite to the direction of force on proton due to right hand rule.

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