Q24.5 In the parallel plate capacitor of Fig. 24.2, suppose the plates are pulle

Question

Q24.5 In the parallel plate capacitor of Fig. 24.2, suppose the plates are pulled apart so that the separation d is much larger than the size of the planets.  (a) Is it still accurate to say that the  E field between the plates is uniform?  Why?  (b) If the potential difference between the plates is Vab = Qd/eA, and the plates are pulled apart, is Vab more or less than this formula would indicate?  Explain!  With the plates pulled apart, is the capacitance more than, less than, or the same as that given by the equation?  Explain.

Explanation / Answer

Answer:

1) when d is very large than size of plate, the E would not be uniform.

both plates would act as separate charge particles

2) No it would not change, because it is the difference of potential at a point due to separate charges

3) Yes capacitance would decrease when pulling apart because C = epsilon A/d

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