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13 1/4 1/8 QUESTION 4 Assume that a black guinea pig crossed with an albino guin

ID: 142731 • Letter: 1

Question

13 1/4 1/8 QUESTION 4 Assume that a black guinea pig crossed with an albino guinea pig produced 5 black offipring When the albino was crossed with a second black guinea pig, 4 black and 3 albino offspring were produced. What genetic explanation would apply to these data? O None of the answers listed is correct. albino-recessive, black-dominant albino and black-codominant O albino recessive; black - recessive O albino - dominant; black- incompletely dominant QUESTION 5 The fundamental Mendelian process that involves the separation of contrasting genetic elements at the same locus woul Save and Submit to save and submit. Click Save All Answers to save all answers. Save

Explanation / Answer

The possible explanation is albino = recessive and black = dominant.

Let's denote the alleles as A and a, with 'A' being the dominant black allele and 'a' being the recessive albino.

Hence the albino guinea pig will be aa.

The first black guinea pig could possibly be homozygous dominant (AA) .Thus a cross between this black guinea pig and the albino will result in all black offsprings with the heterozygous genotype Aa.

The second black guinea pig could be having the heterozygous dominant genotype Aa. Hence a cross of the albino with this guinea pig will yield offsprings with Aa(black) or aa(albino).

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