the capacitor win be How many extra electrons will be on the negative plate of t

Question

the capacitor win be How many extra electrons will be on the negative plate of this capacitor.? You have 4 equal point charges, say 2 Mu C, at the 4 corners of a square : (x, y) = (1cm, 1cm), (1cm, -1cm), (-1cm, 1cm)and|(-1cm, -1cm) What is the electric field at the center of this array of charges? Suppose all is the same as in (3), except that the charge at (1cm, 1cm) is -2Mu C. Use superposition to find the field now at (x,y) = (0, 0). How much work must be done to assemble the four charge array in Example 2? A 1 Omega, 2 Omega, and 3 Omega resistor are connected in series across the terminals of a 6.0 volt battery. How many electrons per second pass through the battery. To turn a galvanometer into a voltmeter I generally have to provide a low shunt resistance in parallel with the meter provide a high shunt resistance in series with the meter

Explanation / Answer

6) R1 = 1 Ohm ; R2 = 2 Ohm and R3 = 3 Ohm ; V = 6 Volts

Let N be the number of electrons.

Since all the three resistors are connected in series, so their equivalent will be:

Req = R1 + R2 + R3 = 1 + 2 + 3 = 6 Ohm

We know from Ohm's law, V = IR => I = V/R = 6/6 = 1 A

We know from the defination of current that,

I = Q/t => Q = I x t = 1 A x 1 s = 1 C

We know that the charge on an electron = e = 1.6 x 10-19 C. So the no of electrons in 1 c of charge will be:

N = 1 C / e = 1 / 1.6 x 10-19 = 6.25 x 1018 electrons

Hence, N = 6.25 x 1018 electrons.

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