Begin Date: 2/26/2016 12:00:00 AM - Due Date: 3/2/2016 11:59:00 PM End Date: 3/2
ID: 1427927 • Letter: B
Question
Begin Date: 2/26/2016 12:00:00 AM - Due Date: 3/2/2016 11:59:00 PM End Date: 3/2/2016 11:59:00 PM Suppose a man stands in front of a mirror as shown in the figure. His eyes are 135 m above the floor, and the top of his head is 0.11 m higher. Randomized Variables h_c = 1.55 m h_h = 0.11 m Find the height above the floor of the bottom of the smallest mirror in which he can see both the top of his head and his feet. Find the height above the floor of the top of the smallest mirror in which he can see both the top of his head and his feet. h_t =Explanation / Answer
Here,
he = 1.55 m
hh = 0.11 m
a)
For the height of the smallest mirror
as he sound be able to see his legs
and the angle of incidence = angle of reflection
hb * 2 = height of eyes
hb * 2 = 1.55
hb = 0.775 m
the height of the bottom of the smallest mirror is 0.775 m
b)
for the height of the top of the mirror
ht = hh + he/2
ht = 1.55 + 0.11/2
ht = 1.55 + 0.11/2
ht = 1.605 m
the height ht is 1.605 m
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.