An air-track glider (m =0.4 kg) is pushed against a Hooke\'s-Law spring (k = 150

Question

An air-track glider (m =0.4 kg) is pushed against a Hooke's-Law spring (k = 150 N/'m), compressing the spring by 10cm. The glider is then released and the glider costs upward dong the slanted track. How far along the tack doc. the glider travel before starting back down? The potential energy of a 4-kg particle is given by U(x, y, z) = -(5 N/m)x2 - (4 N/m^2)y^3. What arc the x^-, y^-, and z-components of the force acting on this particle? If the particle is released from rest at the point (x_0, y_0, z_0) = (0, +2 m,0), what is its speed after traveling a distance of 5 m?

Explanation / Answer

The spring is compressed storing potential energy when it is release this energy changes into kinetic energy of the mass and eventually as the gravitational potential energy of the mass

Hence,

1/2 kx^2 = mgh

1/2 * 150 * .01 = 0.4 *9.8 * h

h = 19 cm

Hence d = h cosec (30)

d = 38 cm

(Please post independent questions seperately)

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