Diagrams A and B show the electric potential along the x-axis in two different s

Question

Diagrams A and B show the electric potential along the x-axis in two different situations. Answer each of the questions below with True (T), False (F), or Can not tell (C). If, for example, the answer to the first question is True, the answer to the second is Can Not Tell, and the answer to the others is False, enter TCFFFF.

1) The electric field at x = 2 m in Diag. B points to the left

2) An electric dipole with its positive charge at y = -0.01 mm and its negative charge at y = 0.01 mm placed at xx= 2 m in Diag. A and released will initially rotate counterclockwise.

3) The work done by you to bring a negative charge from infinity to the point x = 4 m in Diag. B is greater than zero.

4) The magnitude of the electric field at x = 4 m in Diag. A is larger than the magnitude of the electric field at x = 4 m in Diag. B.

5) A negative charge placed at x = 2 m in Diag. A and released will accelerate left.

6) The electric potential at x = 2 m in Diag. A is larger than the electric potential at x = 3 m in Diag. B.

Explanation / Answer

The answer sequence will be TFFFFT

1) Using E = -dV/dx, we get that electric field points always to lower potential

2)Since field is towards left, so dipole will rotate clockwise

3)work done to bring charge from zero potential(infinity) to negative is negative

4)magnitude of electric field at x=4 in Diag 4 is 1, whilw that at x=4 in Diag B is 3/2

5)The field is towards left so negative charge accelerates towards right

6)simply by observation, -2>-47

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