A foot hall is punted at angle of theta with the horizontal such that the horizo

Question

A foot hall is punted at angle of theta with the horizontal such that the horizontal and vertical components of its initial velocity are 40 m/s and 30 m/s respectively. [assume the acceleration due to gravity is 10 m/s1^.] What is the angle theta? The magnitude of the acceleration of the football at the highest point of its trajectory is _m/s The horizontal component of its velocity after 2.0 s is_m/s. A boat with a speed of 30 km/h in still water is aimed directly across a 100 m wide river whose current flows at a rate of 12 km h. the speed of the boat relative to the shore how far downstream the boat travels

Explanation / Answer

vx = 40 m/s

vy = 30 m/s

magnitude of velcoity

v = sqrt vx^2 + vy^2 = 50 m/s

vx = v cos theta

40 m/s = 50 m/s cos theta

theta = cos^-1 ( 40 / 50) = 36.86 = 37 degree option(1) is correct answer

(2) at heighest point velocity of the ball is v = 0 but accleration occurs due to accleration due to gravity

a = 10 m/s^2

(3) horizontal velcoity does not change in projectile motion so 40 m/s

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(5)

F = ma = 0.20 kg ( 10 m/s^2) = 2 N

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