Work done against a force may be interpreted as storing up potential energy. Sup

Question

Work done against a force may be interpreted as storing up potential energy. Suppose work is done against a force f(t) to move an object along the t-axis from t = I to t = r. The potential energy stored is equal to For example, pulling a rope up to the top of a building stores potential energy which may later be released - for instance, as kinetic energy if the rope is thrown off the building. An object of mass m moving at a velocity v has kinetic energy 1/2mu_2. The Earth exerts a gravitational force on an object of mass m (in kilograms) a height h (in metres) above the surface of the Earth of where k and r are positive constants (r is the radius of the Earth). Calculate the work done to raise a 1 kg object to an infinite height.

Explanation / Answer

here,

mass , m = 1 kg

radius of earth , r = 6.371 * 10^6 m

the work done required , W = change in gravitation potential energy

W = 0 - ( - G * m * Me /r)

W = 6.67 * 10^-11 * 1 * 5.97 * 10^24 /( 6.37 * 10^6)

W = 6.25 * 10^7 J

teh work done to raise a 1 kg object to an infinite height is 6.25 * 10^7 J

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