I managed to answer question 25 with FTTF, but I require some assistance with 26

Question

I managed to answer question 25 with FTTF, but I require some assistance with 26, any work on how you derive the final answer would be extremly helpful and appreciated

Assuming that these contours are those of a point charge at the origin, calculate the value of the charge.

25. [lpt] The diagram shows the E field lines (with arrows) and the equipotential contours for a certain charge configuration. Select T-True or F-False for the following statements. If the first is true and the rest false, enter TFFF 7000V 1.0 -9000 V O 0.8 0.6 6000 V 0.4 -8000 V 0.2 0.0 0.0 0.2 0.4 0.6 0.8 1.0 12 1.4 distance (m) i. The equipotential and field lines shown could represent those of a positive point charge ii. The E-Field at B is weaker than at C iii. An electron placed at A will move towards B iv. A dipole with centre at C and free to rotate about C will rotate such that the positive pole swings towards B Answer: Submit All Answers 26. [lpt] Assuming that these contours are those of a point charge at the origin, calculate the value of the charge Answer: Submit All Answers

Explanation / Answer

i) False: Since Electric field lines converges at the point, equi-potential and electric field lines shown are of a negative charge.

ii) True: Since at point B electric field lines are less than electric field lines at C.

iii) True: Since B has higher potential than A, electron will move towards B.

iv) Fase: Since B has higher potential than A, negative pole will move(swings) towards B.

Thus final input : FTTF

Use eqn,

V= kQ/r

When V= -9000V , r= 1.0 m

Thus,

-9000= (9*10^9*Q)/1.0     => Q= -1*10^-6 C = -1.0 µC

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