Two tiny spheres of mass m = 7.80 mg carry charges of equal magnitude, 72.0 nC,

Question

Two tiny spheres of mass m = 7.80 mg carry charges of equal magnitude, 72.0 nC, but opposite sign. They are tied to the same ceiling hook by light strings of length 0.530 m. When a horizontal uniform electric field E that is directed to the left is turned on, the spheres hang at rest with the angle ? between the strings equal to 50.0? in the following figure. (Figure 1)

Item 9 Part A Iwo tiny spheres of mass m = 180 mg carry charges of equal magnitude, 72.0 nC, but opposite sign. They are tied to the same ceiling hook by light strings of length 0.530 m. When a horizontal uniform electric field E that is directed to the left is turned on, the spheres hang at rest with the angle between the strings equal to 50.0° in the following figure Figure 1) Which ball (the one on the right or the one on the left) has positive The one on the right The one on the left Submit My Answers Give Up Part B Figure 1 What is the magnitude E of the field? Express your answer with the appropriate units E-Value Units Submit My Answers Give Up

Explanation / Answer

rge horizontal to the right and the E field horizontal to the left.
We know that the sum of the horizontal forces Fx divided by the vertical force (mass*g) = tan25
We know the distance between the spheres = 2*0.53sin25 = 0.448m
[72e-9*E - k*(72e-9)²/0.448²]/7.8e-6*9.8 = tan25
[72e-9*E - k*(72e-9)²/0.448²] = 7.8e-6*9.8* tan25
[72e-9*E = k*(72e-9)²/0.448²] + 7.8e-6*9.8* tan25
E = [k*(72e-9)²/0.448²] + 7.8e-6*9.8* tan25]/72e-9 = 5,554.6 N/C <------------

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