In a Hall effect experiment, a current of 3.2A lengthwise in a conductor of 1.2

Question

In a Hall effect experiment, a current of 3.2A lengthwise in a conductor of 1.2 cm wide, 4.0 cm long, and 9.5 um thick produces a transverse Hall voltage (across the width) of 40 uV when a magnetic field of 1.4 T acts perpendicular to the thin conductor. From these data, find (a) the drift velocity of the charge carriers and (b) the number density of charge carriers. From Table 32-2, identify the conductor. (c) Show a diagram the polarity of the Hall voltage with a given current and magnetic filed direction, assuming that the charge carriers are (negative) electons.

-I will check the Table 32-2 once I know the information I need (number density of charge carriers I beleive.)

Explanation / Answer

Vh = (I*B)/(ne*d)
Where,
B is Magnetic field
I is current
n is Density of charge carriers
e is charge on electron.
Vh is Hall Voltage

Substituing Values,
40 * 10^-6 = (3.2*1.4)/(n*1.6*10^-19*9.5*10^-6)
n = 7.37 * 10^27 m^3
Number density of charge carriers, n = 7.37 * 10^27 m^3

Drift Velocity is given by,
V = Vh/Bw
V = (40 * 10^-6 )/(1.4 * 1.2 * 10^-2)
V = 2.38 * 10^-3 m/s
Drift Velocity, V = 2.38 * 10^-3 m/s

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