A force of 1.3 Times 10^-4 N is between two charges that are 0.10 cm apart. If o

Question

A force of 1.3 Times 10^-4 N is between two charges that are 0.10 cm apart. If one charge is three times the other charge, what is the charge of the smaller charge? What charge exists on a test charge that experiences a force of 3.4 Times 10^-8 N at a point where the electric field intensity is 5.0 Times 10^-4 N/C? What is the electric field strength between the plates of a 4.00 mF capacitor that are 2.15 cm apart if the electric potential between the plates is 4.54 V. A capacitor that is connected to a 40.0 V source contains 80.0 mu C of charge. What charge would the capacitor contain if it were connected to a 30.0 V source? fur is rubbed with a balloon, the balloon will stick to the fur. Answer

Explanation / Answer

1. F=1.3 x 10^-4 N

r=0.1 cm=10^-3 m

q1=q and q2=3q, to find q

Now as F=kq1q2/r^2 = k(q)(3q)/r^2 = 9e9*3q^2/(10^-3)^2

1.3 x10^-4 = 27e15 *q^2

q^2=1.3 x10^-4/27e15 =0.4815e-20

q=6.94e-11 C

2.F=3.4 x 10^-8 N

E=5 x10^-4 N/C

F=qE

q=F/E = 3.4 x 10^-8/5 x10^-4 =6.8 x10^-5 C

3. C=4e-3 F

d= 2.15 cm = 2.15e-2 m

V=4.54 V

E=V/d= 4.54/2.15e-2 =211.16 V/m

4. As we know charge in case of capacitor is given by, Q=CV

C=Q/V

C is inversely proportional to voltage

C1=Q1/V1

C2=Q2/V2

as C1=C2=C

Q1/V1=Q2/V2

Q2=(Q1/V1)*V2 =80e-6*30/40 = 60e-6 C

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.