1. A hardworking ant must supply 0.00655 N to pull a small piece of fruit at con

Question

1. A hardworking ant must supply 0.00655 N to pull a small piece of fruit at constant velocity over a distance of 9.40 cm up a small hill to the entrance of the colony. If the coefficient of kinetic friction between the piece of fruit and the 17.0o sloped hill is 0.500, calculate the work done by the ant by pulling the piece of fruit up the hill.

W= 6.61 x 10-4 J

2. Use the work-energy theorem to calculate the mass of the piece of fruit in grams. (The acceleration due to gravity is 9.81 m/s2.)

m=________________ g

I just need help with the second question please.

Explanation / Answer

(1) Work done by ant Wa = 0.00655N * 9.40 cm = 0.06157 N·cm = 6.16 x 10^-4 J

(2) Work done by gravity Wg = M * -9.81m/s² * 9.4cm * sin17º = -26.96 N·cm * M
work done by friction Wf = 0.50 * M * -9.81m/s² * 9.4cm = -46.11 N·cm * M
Further, "constant velocity" means that these works sum to zero (no change in KE)
0.06157 = M(26.96 + 46.11)
M = 8.426e-4 kg = 0.8426 g

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