You are standing in the middle of a large room listening to a cacaphony of sound
ID: 1431208 • Letter: Y
Question
You are standing in the middle of a large room listening to a cacaphony of sounds. Rank the intensity level of the sounds from each source (1=loudest, 2= next loudest, ...) Consider all objects to be right next to you. If two values are within 0.1 dB from each other, consider them to be the same.
1 2 3 4 5 Ten buzzers each producing a sound with intensity level of 70dB.
1 2 3 4 5 Two buzzers each producing a sound with intensity level of 77dB.
1 2 3 4 5 Four buzzers each producing a sound with intensity level of 74dB.
1 2 3 4 5 One hundred buzzers each producing a sound with intensity level of 60dB.
1 2 3 4 5 An object emitting a sound with an intensity level of 80dB
Explanation / Answer
The intensity of 1 70 dB buzzer is I = 10^(70/10)*10^-12 (From the intensity eqn) = 10^-5 so 10 would produce 10^-4 W/m^2 which is 10dB*log(10^-4/10^-12) = 80dB
The intensity of 1 77dB buzzer is I = 10^(77/10)*10^-12 (From the intensity eqn) = 5.0x10^-5 so 2 would produce 1x10^-4 W/m^2 which is 10dB*log(1x10^-4/10^-12) = 80dB
The intensity of 1 74 dB buzzer is I = 10^(74/10)*10^-12 (From the intensity eqn) = 2.51x10^-5 so 4 would produce 1.0x10^-4 W/m^2 which is 10dB*log(1.0x10^-4/10^-12) = 80dB
The intensity of 1 60 dB buzzer is I = 10^(60/10)*10^-12 (From the intensity eqn) =10^-6 so 100 would produce 10^-4 W/m^2 which is 10dB*log(10^-4/10^-12) = 80dB
The intensity of 1 80 dB buzzer is I = 10^(80/10)*10^-12 (From the intensity eqn) =10^-4 so 1 would produce 10^-4 W/m^2 which is 10dB*log(10^-4/10^-12) = 80dB
all are same
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