1. Consider light with a wavelength of 515 nm is passing through a diffraction g

Question

1. Consider light with a wavelength of 515 nm is passing through a diffraction grating with 1,104 lines per cm.   At what distance from the central bright maximum will the 1st order maximum be seen on a screen placed 1.20 m from the diffraction grating.   Give your answer in centimeters (cm) with 3 significant figures.

2. Unpolarized light with an intensity of 25.0 units is passed through two successive polarizing filters, the first with its polarization axis aligned with the vertical and the second with its polarization axis rotated 60 from the vertical. Find the intensity of the light after passing through the two polarizing filters. Give your answer in same unit as the original light and with 3 significant figures.

Explanation / Answer

1)

wavelength = 515 nm

lines = 1104 lines/cm

screen distance , D = 1.20 m

slit seperation , d = 1/1104 cm

d = 9.06 *10^-4 cm = 9.06 *10^-6 m

for the spacing of first maximum

y = wavelength * D/d

y = 515 *10^-9 * 1.20/9.06 *10^-6

y = 6.82 *10^-4 m

y = 0.068 m

the distance of first maxima will be 0.068 m

2)

I = 25 unit

let the final intesity is If

after passing through two polarizers

If = 0.5 * I * cos(theta)^2

If = 0.5* 25 * cos(60)^2

If = 3.13 unit

the final intensity at the output will be 3.13 unit

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