(a) How long would it take a 1.00 105 kg airplane with engines that produce a ma

Question

(a) How long would it take a 1.00 105 kg airplane with engines that produce a maximum of 100 MW of power to reach a speed of 250 m/s and an altitude of 12.0 km if air resistance were negligible? Incorrect: Your answer is incorrect. s (b) If it actually takes 925 s, what is the power applied, in megawatts? Incorrect: Your answer is incorrect. MW (c) Given this power, what is the average force of air resistance if the airplane takes 1200 s? (Hint: You must find the distance the plane travels in 1200 s assuming constant acceleration.)

Explanation / Answer

A)
Mass, M = 10^5 kg
Power, P = 100*10^6 W
Final Speed, v = 250 m/s
Altitude, h = 12000m
Time = t

Pt = 0.5Mv^2+Mgh
t = 148.85 s

B)
Pt = 148.85*10^8 = P*925
P = 16.09 MW

C)
Distance, s = a*1200 (a = constant acc)
but 250 = a(1200) => a = 0.2083 m/s/s
s = 250m

Now, t = 1200s
Peff*1200 = 148.85*10^8
Peff = 12.40 MW
P loss due to air = 3.685 MW
Pt = Fav*250
Fav = 17.692 MN

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.