only last part! A coal car m_j = 4578 kg is rolling down the tracks at a velocit

Question

only last part!

A coal car m_j = 4578 kg is rolling down the tracks at a velocity of v_i = 2.8 m/s when a loader drops a load of coal m_2 = 5695 kg into the car. Randomized Variables m_1= 4578 kg m_2 = 5695 kg V_i = 2.8 m/s What is the momentum of the system in (kg*m)/s before the coal is added? What is the velocity after the coal is added in meters per second? If you measured the final velocity of the car to be 1 m/s and the initial mass of the car remains the same, how much coal was added to the car in kg? Grade Summary m2 =

Explanation / Answer

m1V1= (m1 +M)V
4578*2.8 = (4578+M)*1

M= 8240.4 kg

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