(Already calculated) The tension of the top wire is 263 N. What needs to be solv

Question

(Already calculated) The tension of the top wire is 263 N.

What needs to be solved for:

1) Find the tension in each of two bottom wires.

and

2) How hard does each ball push on the other one?

Problem 5.87 Part B Two identical 13.4-kg balls, each 29.4 cm in diameter, are suspended by two 35.0-cm wires as shown in the figure (Figure 1). The entire apparatus is supported by a single 18.0-cm wire, and the surfaces of the balls are perfectly smooth Find the tension in each of two bottom wires T 142 Submit My Answers Give Up Figure 1 of 1 Incorrect; Try Again; 3 attempts remaining you may have made a rounding error or used the Not quite. Check through your calculations; wrong number of significant figures 18.0 CIn Part C How hard does each ball push on the other one? 35.0 35.0 em Submit My Answers Give Up

Explanation / Answer

Distance from attachment point to centre of each ball = (35 + 14.7) = 49.7cm.

Distance from each ball to the centre of the ball = 14.7cm. (the radius).

Total normal weight of system = (13.4 x 2) x 9.8 = 262.64N. Halve it, as both masses are equal, and the angles

from normal of both suspending wires are equal. (262.64/2) = 131.32N.

Sin angle from normal of each wire = (14.7/49.7), Angle = 17.20degrees.

131.32N/(cos 17.20) = 137.46N. tension in each wire.

2)

Sqrt. (137.46^2 - 131.32^2) =40.7N. each ball applies to the other.

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