Based on the way the velocity is changing, explain the sign and magnitude of the
ID: 1433516 • Letter: B
Question
Based on the way the velocity is changing, explain the sign and magnitude of the acceleration of the coin in the first question during the three portions of its motion: on the way up, at the instant when it reaches its highest point, and on the way down.
The slope of velocity vs. time is always negative and constant, therefore, the acceleration is negative and constant during the three portions.
On the way up, the velocity decreases, so slope < 0 and a < 0. On the way down, the speed increases so that the velocity becomes more and more negative, so slope < 0 and a < 0.
On the way up, the velocity decreases, so slope < 0 and a < 0. At the top, the velocity is zero, so the slope is unknown and the acceleration is unknown . On the way down, the velocity increases, so slope > 0 and a > 0.
On the way up, the velocity decreases, so slope < 0 and a < 0. At the top, the velocity is constant, so slope = 0 and a = 0. On the way down, the velocity increases, so slope > 0 and a > 0.
On the way up, the velocity increases, so slope > 0 and a > 0. At the top, the velocity is constant, so slope = 0 and a = 0. On the way down, the velocity decreases, so slope < 0 and a < 0.
On the way up, the velocity increases, so slope > 0 and a > 0. At the top, the velocity is zero, so the slope is unknown and the acceleration is unknown . On the way down, the velocity decreases, so slope < 0 and a < 0.
The Answer is not D
The slope of velocity vs. time is always negative and constant, therefore, the acceleration is negative and constant during the three portions.
On the way up, the velocity decreases, so slope < 0 and a < 0. On the way down, the speed increases so that the velocity becomes more and more negative, so slope < 0 and a < 0.
On the way up, the velocity decreases, so slope < 0 and a < 0. At the top, the velocity is zero, so the slope is unknown and the acceleration is unknown . On the way down, the velocity increases, so slope > 0 and a > 0.
On the way up, the velocity decreases, so slope < 0 and a < 0. At the top, the velocity is constant, so slope = 0 and a = 0. On the way down, the velocity increases, so slope > 0 and a > 0.
On the way up, the velocity increases, so slope > 0 and a > 0. At the top, the velocity is constant, so slope = 0 and a = 0. On the way down, the velocity decreases, so slope < 0 and a < 0.
On the way up, the velocity increases, so slope > 0 and a > 0. At the top, the velocity is zero, so the slope is unknown and the acceleration is unknown . On the way down, the velocity decreases, so slope < 0 and a < 0.
Explanation / Answer
On the way up, the velocity decreases, so slope < 0 and a < 0. At the top, the velocity is zero, so the slope is unknown and the acceleration is unknown . On the way down, the velocity increases, so slope > 0 and a > 0.
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