When the switch in (Figure 1) is open, the voltmeter V across the battery reads

ID: 1433997 • Letter: W

Question

When the switch in (Figure 1) is open, the voltmeter V across the battery reads 3.08 V . When the switch is closed, the voltmeter reading drops to 2.95 V and the ammeter A reads 1.72 A . Assume that the two meters are ideal, so that they don't affect the circuit.

Part A Problem 19.24 Find the emf. Express your answer in volts to three significant figures. When the switch in (Figure 1) is open, the voltmeter V across the battery reads 3.08 V.When the switch is closed, the voltmeter reading drops to 2.95 V and the ammeter A reads 1.72 A . Assume that the two meters are ideal, so that they don't affect the circuit Submit My Answers Give Up Part B Find the internal resistance of the battery Express your answer in ohms to three significant figures Submit My Answers Give Up Figure 1 of 1 Part C Find the circuit resistance R Express your answer in ohms to three significant figures Submit My Answers Give Up

Explanation / Answer

Solution:

A) The EMF is the voltage of thebattery , in the open circuit , ignoring Internal resistance.

EMF = 3.08 V

B) The difference in voltage is due to internal resistance .

E-V = 3.08 - 2.95 = 0.13 V

Current = I = 1.72A

Internal Resistance = R = 0.13/1.72 = 0.0756 ohms = 7.56 x 10^-2 ohms

C) Circuit resistance = voltage after switch is closed / current = 2.95/ 1.72 = 1.72 ohms

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When the switch in (Figure 1) is open, the voltmeter V across the battery reads

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