In the lab, you found that the \"drag force\" depends linearly on the object\'s

Question

In the lab, you found that the "drag force" depends linearly on the object's velocity. If the drag coefficient was measured to be c = 0.052 N s/m and the object has a mass of 0.0022 kg, what is the magnitude of the terminal velocity for this object? At high velocities, the drag force is seen to depend on the square of the velocity of the object. Suppose you are told that the terminal velocity for a fast moving mass of 0.077 kg is 20 m/s. What is the drag coefficient for this v^2 dependent air resistance? When an object reaches terminal velocity, what will be the net force acting on the object at that time? A sky diver (m = 82.0 kg) jumps out of an airplane at 20,000 feet and has a v2 drag coefficient of D = 0.36 kg/m. Find the terminal velocity for this diver in air.

Explanation / Answer

Fd = cv

Fg = mg

net force = Fg - Fd

when the body is moving at terminal velocity net force = 0

Fd = Fg

cv = mg

0.052*v = 0.0022*9.8

v = 0.414 m/s <<<_----answer

________________________

Fd = cv^2

Fg = mg

Fnet = 0

Fd = Fg

D*v^2 = mg

D*20^2 = 0.077*9.8

D = 0.0018865 kg /m

______________

at tereminal velocity net force = 0

_________________

Fd = Fg

D*v^2 = mg

0.36*v^2 = 82*9.8

v = 47.25 m/s <<<------------answer

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