a.) Find the magnetic field at the center of the circular loop due to the straig
ID: 1434631 • Letter: A
Question
a.) Find the magnetic field at the center of the circular loop due to the straight wire.
b.) Find the magnetic field at the center of the circular loop due to circular wire.
d.) Find the distance wire 3 must be from the point and tell the direction of its current needed to produce no net magnetic field at the point P.
e.) Find the magnetic force per length on wire 3 due to the original straight wire?
Written Problem 1: (This problem is worth a total of 30pts.) A circular wire with a radius of 10 cm has a current of 2 A going through it in the the same time, a long straight wire is placed 30 cm away from the center of the circular wire and has a clockwise direction. At current of 3.5 A through it going upwards.Explanation / Answer
given,
r = 10 cm = 0.1 m
I1 = 2 A
d = 30 cm = 0.3 m
I2 = 3.5 A
a) at the center of the loop, B_wire = mue*I2/(2*pi*d)
= 4*pi*10^-7*3.5/(2*pi*0.3)
= 2.33*10^-6 T (out of the page)
b) at the center of the loop, B_loop = mue*I1/(2*r)
= 4*pi*10^-7*2/(2*0.1)
= 1.26*10^-5 T (into the page)
c)
at the center of the loop, Bnet = B_loop - B_wire
= mue*I1/(2*r) - mue*I2/(2*pi*d)
= 4*pi*10^-7*2/(2*0.1) - 4*pi*10^-7*3.5/(2*pi*0.3)
= 1.02*10^-5 T
magnetic force on electron, F = q*v*Bnet
= 1.6*10^-19*1.5*10^-4*1.02*10^-5
= 2.45*10^-28 N
d) here, B2 = B3, and the direction of B2 and B3 should be opposite.
Apply, B3 = B2
mue*I3/(2*pi*d3) = mue*I2/(2*pi*d2)
d3 = I3*d2/I2
= 7*0.3/3.5
= 0.6 m
Direction : downward
e)the magnetic force per length on wire 3 due to the original straight wire,
F/L = mue*I2*I3/(2*pi*d12)
= 4*pi*10^-7*3.5*7/(2*pi*0.3)
= 1.63*10^-5 N/m
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