Rail gun In the picture rod=rail We are designing a \"magnetic gun\" and the pic

Question

Rail gun

In the picture rod=rail

We are designing a "magnetic gun" and the picture shows a model of one. The bullet is maid out of thin metal bar that conducts, it weights 12 g and is 7.0 cm long, and it lies on a conductive rails and touch it so that current runs easily through. The bar will run out after the rails like the picture shows and the length of the rails are 20 cm. Perpendicular to the current circuit is 0.05 T magnetic field (directed down).

a) Find the direction of the current and how much steady current is needed to run through the metal bar so it will move at 10 m/s after the bar has moved 20 cm out after the rails.

b) Can you expect that the voltage (E) that pushes the steady current through the circuit to change while the bar moves along the rails ? Explain your answer

Help please. Need good explanations

Explanation / Answer

a) Direction of current: from top to bottom for outward force
Force = BIL = ma -- (1)
2as = v^2
a = 100/2*0.2 = 250 m/s^2
I = 0.012*250/0.05*0.07 = 857.14 A

b) The voltage changes because of changing flux through the circuit (faraday's induction). This current in opposite direction is due to back emf

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