#1a: An electrical current of 6.50 mA exists in a solid cylindrical wire whose d
ID: 1435066 • Letter: #
Question
#1a: An electrical current of 6.50 mA exists in a solid cylindrical wire whose diameter is 1.50 mm. Calculate the magnitude of the current density in the wire. Put your answer in the form of "a.bc x 10^(x)" A/m2.
#1b: Assume that electrons are the charge carriers and the conduction electron density is 4.55 x 1029/m3. (Note that this is the charge carrier density and could also be stated as 4.55 x 1029 charge carriers/m3 or electrons/m3.) Calculate the electron drift speed in the wire. Put your answer in the form of "a.bc x 10^(x) m/s".
Explanation / Answer
#1a : electrical current = 6.50 mA = 6.50 * 10-3 A
diameter is = 1.50 mm
Cross section Area = 3.14*(1.50/2)2 = 1.77 mm2 = 1.77 * 10-6 m2
the magnitude of the current density in the wire = 3.68 * 103 A/m2
.#1b:
the conduction electron density is 4.55 x 1029/m3
electron drift speed in the wire = V
neAV = Current
or 4.55 x 1029*1.6*10-19* 1.77 * 10-6*V = 6.50 * 10-3
or V = 5.25 * 10-8 m/s
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