For each of the following combinations of capacitors match the equivalent capaci

Question

For each of the following combinations of capacitors match the equivalent capacitance. (All capacitances are in mu F.) In the circuit below, the capacitor is initially uncharged. When the switch is closed, the bulb never gets brighter because the capacitor is an insulator. starts dim and gets brighter and brighter as more and more charge accumulates on the capacitor starts bright, then gets dimmer and dimmer slowly until it goes out. starts bright and remains the same because the circuit is closed. starts bright, and gets brighter and brighter slowly for some time and finally stays the same. In Question 7 how would your observations be changed if the capacitor were twice as large? The bulb would start bright, then gets dimmer and dimmer for a longer time and finally goes out. The bulb would start bright, then gets dimmer and dimmer for a short time and finally goes out. The bulb would still not get brighter because the capacitor is an insulator. The bulb would start brighter, and stays the same. The bulb would start bright, and gets brighter and brighter for some time and finally stays the same. The bulb would start dim, and gets brighter in a shorter time. How would your observations in Question 7 be changed if the bulb had half as much resistance? The bulb would start brighter, then gets dimmer and turns off in a longer time. The bulb would start dim and gets brighter in a short time. The bulb would start less bright and remains the same. The bulb would still not get bright because the capacitor is an insulator. The bulb would start brighter, then gets dimmer and turns off in a shorter time. In the circuit below, the capacitor is initially charged. It has capacitance of 0.023F, while the resistor has resistance 47 Ohm. How long after the switch is closed does the voltage on the capacitor fall to 37% of its initial value? 2043s 0.00049s 1.21s 2.1s 1.1s

Explanation / Answer

6)a. 1/Ceq= 1/20 +1/30 +1/30

Ceq= 15e-6 ohm

b. 1/Ceq = 1/(20*30/20+30) +1/30

Ceq = 10e-6 ohm

c. C=10+20+30+40 = 100e-6 ohm

7. starts bright, and get brighter and brighter slowly for some time and finally stays the same.

8.The bulb would start dim and gets brighter in a shorter time

9. The bulb would start brighter, then gets dimmer and turn off in a longer time

10. 0.37 =e-t/RC= e^-t/47*0.023=e^-t/1.081

ln(0.37)=-t/1.081

-0.99=-t/1.081

t=1.1 s

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