A silver dollar is dropped from the top of a building that is 1363 feet tall. Us
ID: 1436063 • Letter: A
Question
A silver dollar is dropped from the top of a building that is 1363 feet tall. Use the position function below for free-falling objects.
s(t) = 16t2 + v0t + s0
(a) Determine the position and velocity functions for the coin.
(b) Determine the average velocity on the interval [3, 4].
3 ft/s
(c) Find the instantaneous velocities when t = 3 seconds and t = 4 seconds.
(d) Find the time required for the coin to reach the ground level. (Round your answer to three decimal places.)
t = 6 s
(e) Find the velocity of the coin at impact. (Round your answer to three decimal places.)
7 ft/s
Explanation / Answer
a) s(t) = -16*t^2 + 1363
v(t) = -32*t
b) Vavg = [s(4) - s(3)]/(4-3) = -112 ft/s
c) v(3) = -32*3 = -96 ft/s
v(4) = -32*4 = -128 ft/s
d) s(t) = -16*t^2 + 1363 = 0 =====> t = 9.23 sec
e) v(9.23) = -32*9.23 = -295.36 ft/s
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.