I am giving you the solution to the problem. Just replace with my numbers and fo

Question

I am giving you the solution to the problem. Just replace with my numbers and follow the procedure.

Problem:

Solution:

Problem 15.69 A 280 g ball is kicked with a velocity of vA 25 m/s at point A as shown. Figure 1 of 1 v 25 m/s 30 Part A If the coefficient of restitution between the ball and the field is e E 0.6, determine the magnitude of the velocity of the rebounding ball at B (Figure 1) Express your answer with the appropriate units. Value Units Submit My Answers Give U Part B Determine the direction 6 of the velocity of the rebounding ball at B Express your answer with the appropriate units Value Units Submit My Answers Give U Provide Feedback Continue

Explanation / Answer

v'Bx = vBx

= 25*cos(30)

= 21.65 m/s

vBy = 25*sin(30)

= 12 .5 m/s

we know,

e = -(0 - v'By)/(vBy - 0)

0.6 = v'By/12.5

v'By = 0.6*12.5

= 7.5 m/s

so, at point B,

v'B = sqrt(v'Bx^2 + v'By^2)

= sqrt(21.65^2 + 7.5^2)

= 22.9 m/s <<<<<<<<--------------------Answer

angle, theta = tan^-1( v'By/v'Bx)

=tan^-1(22.9/21.65)

= 46.6 degrees   <<<<<<<<--------------------Answer

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.