In the figure, a conducting rod of length L = 29.0 cmmoves in a magnetic field B

Question

In the figure, a conducting rod of length L = 29.0 cmmoves in a magnetic field B?  of magnitude 0.550 Tdirected into the plane of the figure. The rod moves with speed v = 6.00 m/s in the direction shown.

Part C

When the charges in the rod are in equilibrium, what is the magnitude E of the electric field within the rod?

Express your answer in volts per meter to at least three significant figures.

Part E

What is the magnitude Vba of the potential difference between the ends of the rod?

Express your answer in volts to at least three significant figures.

Part F

What is the magnitude E of the motional emf induced in the rod?

Express your answer in volts to at least three significant figures.

Explanation / Answer

1)when the rod is in motion charges experience magnetic force in presence of magnetic field and
according to Force(magnetic) = q*[cross product of velocity and field]
if velocity is on -ve y-axis and field inside the plane then by Right hand Screw rule positive charges experience force towards point P and negative charges accumulate at point A and hence naturally their is attractive coulombic force between charges so in steady condition these forces balance each other and Hence
q*v*B = q*E
E = v*B = 6*0.55 = 3.3 N/C

2) Vab = E*l = 3.3*0.29 = 0.957 V

3)

Motional emf is the potential difference generated by moving a conducting rod through a magnetic field. The

motional emf is measured between the two ends of the rod.

emf = V = E*l = 0.957 V

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