cs.com/ ?assignmentProblemiD-SSearch NIVERSITY PHYSICS II (PHYS2326 Ch23HWExerci

Question

cs.com/ ?assignmentProblemiD-SSearch NIVERSITY PHYSICS II (PHYS2326 Ch23HWExercise 23.5 Exercise 23.5 Part A A small metal sphere, carrying a net charge of 260 What is the speed of when the spheres are 0400 m apart? pCrs held i, a stationary positon by insulating supports. A second smal metal sphere, with a net charge of g1 =750 C and mass 140g,sprogected toward gi When the two spheres are 0 800 m apart, 9 s moving toward q with speed 22.0 m/s (Eigure 1) Assume that the two spheres can be treated as point charges. You can ignore the force of gravity ? m/s My Answers Give Up Part B How close does get to q1 Figure 1 of1 rn Mty Answers Gihve U ubmit 92 u=22.0 mls q1 0.800 m

Explanation / Answer

here,

q1 = - 2.6 * 10^-6 C

q2 = - 7.5 * 10^-6 C

m2 = 0.0014 kg

x1 = 0.8 m

v2 = 22 m/s

A)

let the speed of q1 be v3 when x2 = 0.4 m

using conervation of energy

0.5 * m * v2^2 + k * q1*q2/x1 = 0.5 * m * v3^2 + k * q1*q2/x2

0.5 * 0.0014 * 22^2 + 9 * 10^9 * 10^-12 * 2.6 * 7.5 /0.8 = 0.5 * 0.0014 * v3^2 + 9 * 10^9 * 10^-12 * 2.6 * 7.5 /0.4

v3 = 13.06 m/s

the speed of the charge q2 is 13.06 m/s

B)

when speed is zero let the distance between charges be x

0.5 * m * v2^2 + k * q1*q2/x1 = 0.5 * m * 0^2 + k * q1*q2/x

0.5 * 0.0014 * 22^2 + 9 * 10^9 * 10^-12 * 2.6 * 7.5 /0.8 = 9 * 10^9 * 10^-12 * 2.6 * 7.5 /x

x = 0.31 m

the sepration between charges is 0.31 m

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