Must know this information to answer question below. Assume the Milky Way contai

ID: 1436438 • Letter: M

Question

Must know this information to answer question below.

Assume the Milky Way contains 100 billion stars evenly distributed with none concentrated toward the center.

What would be the surface area density of stars? Use the equation surface area density = number of stars/surface area.

Answer: Surface Area Density = (100*10^9 stars)/(7.85*10^9 ly^2) = 12.7 stars/ly^2

Question

Assume the Milky Way contains 100 billion stars evenly distributed with none concentrated toward the center.

Use this information to figure out the average amount of space around a single star in units of AU (Note: 1 light-year = 63,000 AU.)

average amount of space around a single star = Total surface Area / Total No. of stars

= 7.85*10^9 ly^2 / 100*10^9 stars = 0.0785 ly^2

we know that 1 light year = 63,000 AU

hence 0.0785 ly^2 * 63,000 AU*63,000 AU = 311566500 AU2

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