Two point charges of equal magnitude are 5.4 cm apart. At the midpoint of the li

Question

Two point charges of equal magnitude are 5.4 cm apart. At the midpoint of the line connecting them, their combined electric field has a magnitude of 75 N/C. Find the magnitude of the charges. Two point charges of equal magnitude are 5.4 cm apart. At the midpoint of the line connecting them, their combined electric field has a magnitude of 75 N/C. Find the magnitude of the charges. Two point charges of equal magnitude are 5.4 cm apart. At the midpoint of the line connecting them, their combined electric field has a magnitude of 75 N/C. Find the magnitude of the charges.

Explanation / Answer

Here ,

let the magnitude of charge is q

distance ,d = 5.4 cm

distance from the midpoint , r = d/2 = 2.7 cm

Now , for the electric field at the midpoint

E = 2 * k * q/r^2

75 = 2 * 9*10^9 * q/0.027^2

solving for q

q = 3.04 *10^-12 C

the magnitude of the charges is 3.04 *10^-12 C

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