As the electron gains kinetic energy, does its electric potential energy increas

Question

As the electron gains kinetic energy, does its electric potential energy increase or decrease?

The difference in the electron's electric potential energy between the positive and negative plates is EPEpositive - EPEnegative. How is this difference related to the charge on the electron (-e) and to the difference Vpositive - Vnegative in the electric potential between the plates?

How is the potential difference Vpositive - Vnegative related to the electric field within the capacitor and to the displacement s of the positive plate relative to the negative plate? Assume that the direction to the right in the drawing is the positive direction.

In the drawing, the direction to the right is positive. The plates of a parallel plate capacitor are separated by a distance of 1.7 cm, and the electric field within the capacitor has a magnitude of 4.6 106 V/m. Note that the electric field points in the negative direction. An electron starts from rest at the negative plate and accelerates to the positive plate

What is the algebraic expression that gives the kinetic energy KEpositive of the electron as it reaches the positive plate of the capacitor? Express your answer in terms of the charge e on the electron, the electric field E, and the electron's displacement s (which is also the displacement of the positive plate relative to the negative plate).

What is the kinetic energy KEpositive of the electron just as the electron reaches the positive plate?

Explanation / Answer

As the electron gains kinetic energy , its potential energy decreases   . since Potential energy converts to kinetic energy.

EPEpositive - EPEnegative = - e (Vpositive - Vnegative)

Electric field = E = (Vpositive - Vnegative) / s

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