A light ray traveling from a higher index of refraction medium into a lower inde

Question

A light ray traveling from a higher index of refraction medium into a lower index of refraction medium (for example, from water into air) would bend away from the normal to the medium surface. When the refracted ray is parallel to the boundary of the medium, ?2= 90°. The incident angle, ?1, becomes ?c, called the

A light ray is incident on a reflecting surface. If the light ray makes a 45° angle with respect to the normal to the surface, what is the exact angle (in degrees) made by the reflected ray relative to the normal? Do not include units with your answer.

Explanation / Answer

Here,

When the refracted ray is parallel to the boundary of the medium

then the angle of incidence is called Critical angle.

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theta1 = 45 degree

for the reflected ray

angle of incidence = angle of reflection

angle of incidence = 45 degree

angle of reflection = 45 degree

the exact angle made by the reflected ray relative to the normal is 45 degree

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there is no question for true or false

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