The solar wind is a thin, hot gas given off by the sun. Charged particles in thi

Question

The solar wind is a thin, hot gas given off by the sun. Charged particles in this gas enter the magnetic field of the earth and can experience a magnetic force. Suppose a charged particle traveling with a speed of 8.80 106 m/s encounters the earth's magnetic field at an altitude where the field has a magnitude of 1.10 10-7 T. Assuming that the particle's velocity is perpendicular to the magnetic field, find the radius of the circular path on which the particle would move if it were each of the following.

Explanation / Answer

radius of the circular path r = (m*v)/(q*B)

m is the mass of the charged particle

q is the charge of the charged particle

v is the speed of the cahrged particle

and B is the magnetic field

then r = (m*8.8*10^6)/(q*1.1*10^-7)

if that charged particle is an electron

then r = (9.11*10^-31*8.8*10^6)/(1.6*10^-19*1.1*10^-7) = 455.5 m

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