please explain in detail 15. An electron is initially moving along the x-axis at

Question

please explain in detail

15. An electron is initially moving along the x-axis at 12 m/s when it hits a series of regions of space. The regions of space contain a constant electric field that is oriented along the y-axis with a magnitude of 10 N/C, each having a length of 10 m, and the electric fields alternate in the plus and minus direction with the first region being in the -y-direction so that region one is directed along -y, region 2 is directed along +y, and so on. Determine the equations of motion of the electron for its position, velocity, and acceleration. The magnitudes of the charge and mass of an electron are e 1.60 x 10 19 C and m 9.109 x 10 kg, respectively.

Explanation / Answer

accleration of the charge is ma = Eq

so

a long y axis ay = Eq/m

ay = (10 *1.6e -19)/9.11 e-31

ay = 1.75 e 12 m/s^2

so

time t = v/a = 10/1.75 e -12

t = 5.71 *10^-12 secs

so

eqution for position is S = ut - 0.5 at^2

x = (10* 5.71 e -12) -(0.5* 1.75 e 12 * 5.71 e -12 * 5.71 e -12)

----------------------------

Velocity V = u + at

V = 10 + (1.75 e 12 * 5.71 e -12)

----------------------------------------------

accleration a = V/t

a = 10/(5.71 e -12)

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.