The mass of a rigid rod is 0.20 kg and its length is 48.0 cm. Calculate the mome
ID: 1437451 • Letter: T
Question
The mass of a rigid rod is 0.20 kg and its length is 48.0 cm. Calculate the moment of inertia (in kg · m2) for the rod if it is pivoted about an axis through the center of mass of the rod. (Assume the axis is perpendicular to the rod. Enter your answer to at least three significant figures.)
I = kg · m2
What is the physical meaning of the moment of inertia? Pick one
The moment of inertia is the angular momentum of the object at a given instant in time.
The moment of inertia is a measurement of how much the object resists angular rotation.
The moment of inertia is a measurement of how the radius of an object changes while it is rotating.
The moment of inertia is equivalent to the mass of the object.
Explanation / Answer
The mass of a rigid rod is 0.20 kg and its length is 48.0 cm.
moment of inertia for the rod if it is pivoted about an axis through the center of mass of the rod. (Assume the axis is perpendicular to the rod. ) - M*L*L/12.
SO moment of inertia is .20 *48*48 *10^-2*10^-2/12 = 38.4 *10^-4 Kgm^2.
The moment of inertia is a measurement of how much the object resists angular rotation.
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